怎么编程画一棵圣诞树

时间:2025-01-25 13:16:50 游戏攻略

1. 使用C语言绘制圣诞树

方法一:使用标准输出

```c

include

int main() {

int height = 10;

for (int i = 0; i < height; i++) {

for (int j = 0; j < height - i - 1; j++) {

printf(" ");

}

for (int k = 0; k < 2 * i + 1; k++) {

printf("*");

}

printf("\n");

}

for (int i = 0; i < 3; i++) {

for (int j = 0; j < rows - 2; j++) {

printf(" ");

}

for (int k = 0; k < 5; k++) {

printf("*");

}

printf("\n");

}

return 0;

}

```

方法二:使用Sierpinski三角形

```c

include

include

define PI 3.14159265359

float sdCircle(float px, float py, float r) {

float dx = px - sx, dy = py - sy;

return sqrtf(dx * dx + dy * dy) - r;

}

float opUnion(float d1, float d2) {

return d1 + d2 - sqrtf(d1 * d1 + d2 * d2);

}

int main(int argc, char* argv[]) {

int n = argc > 1 ? atoi(argv) : 4;

for (int j = 1; j <= n; j++) {

int size = 200 / (j + 1);

for (int i = 0; i < size; i++) {

float x = size / 2 + i * (size - 1);

float y = size / 2 - j * size;

float d = sdCircle(x, y, size / 2);

float nx = x + d * cos(PI / 6);

float ny = y + d * sin(PI / 6);

float nx1 = x - d * cos(PI / 6);

float ny1 = y - d * sin(PI / 6);

float d1 = sdCircle(nx, ny, size / 2);

float d2 = sdCircle(nx1, ny1, size / 2);

float area = opUnion(d, d1) + opUnion(d, d2) - d * d;

printf("%f\n", area);

}

}

return 0;

}

```

2. 使用Python绘制圣诞树

方法一:使用pygame库