编程怎么做3d迷宫游戏

时间:2025-01-25 10:21:26 游戏攻略

制作迷宫游戏的方法有很多种,这里提供几种不同的实现方式:

1. 使用二维数组表示迷宫

你可以使用二维数组来表示迷宫的结构,其中0代表墙壁,1代表路径,2代表终点。以下是一个简单的示例代码:

```cpp

include

using namespace std;

void displayMaze(int maze[], int rows, int cols) {

for (int i = 0; i < rows; i++) {

for (int j = 0; j < cols; j++) {

if (maze[i][j] == 0) {

cout << "";

} else if (maze[i][j] == 1) {

cout << " ";

} else if (maze[i][j] == 2) {

cout << "E";

}

}

cout << endl;

}

}

int main() {

int maze = {

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 1},

{0, 1, 0, 1, 0, 1, 0, 1, 0, 2}

};

int playerX = 1;

int playerY = 1;

while (true) {

displayMaze(maze, 10, 10);

char direction;

cin >> direction;

if (direction == 'w' && maze[playerX - 1][playerY] != 0) {

playerX--;

} else if (direction == 's' && maze[playerX + 1][playerY] != 0) {

playerX++;

} else if (direction == 'a' && maze[playerX][playerY - 1] != 0) {

playerY--;

} else if (direction == 'd' && maze[playerX][playerY + 1] != 0) {

playerY++;

}

if (maze[playerX][playerY] == 2) {

cout << "You reached the exit!" << endl;

break;

}

}

return 0;

}

```

2. 使用3D引擎生成迷宫

你可以使用3D引擎如Ursina来生成和显示迷宫。以下是一个使用Ursina和numpy生成随机迷宫的示例: