编程上怎么做加减运算法则

时间:2025-01-25 15:06:08 游戏攻略

在编程中实现加减运算的方法取决于你使用的编程语言。以下是几种常见编程语言中实现加减运算的示例:

Java

```java

import java.util.Scanner;

public class CalculatorApp {

public static void main(String[] args) {

Scanner scanner = new Scanner(System.in);

System.out.println("请输入第一个数字:");

double num1 = scanner.nextDouble();

System.out.println("请输入运算符(+ 或 -):");

char operator = scanner.next().charAt(0);

System.out.println("请输入第二个数字:");

double num2 = scanner.nextDouble();

double result;

switch (operator) {

case '+':

result = num1 + num2;

break;

case '-':

result = num1 - num2;

break;

default:

System.out.println("无效的运算符");

return;

}

System.out.println("结果是: " + result);

}

}

```

C++

```cpp

include

using namespace std;

int main() {

cout << 5 + 3 << endl;

cout << 5 - 3 << endl;

cout << 5 * 3 << endl;

cout << 5 / 3 << endl;

return 0;

}

```

C语言

```c

include

int main() {

int a = 10, b = 20, sum = a + b;

printf("Sum: %d\n", sum);

a = 30, b = 10, int difference = a - b;

printf("Difference: %d\n", difference);

int a = 5, b = 6, int product = a * b;

printf("Product: %d\n", product);

float a = 20, b = 4, float quotient = (float)a / (float)b;

printf("Quotient: %.2f\n", quotient);

return 0;

}

```

Python

```python

num1 = float(input("请输入第一个数字: "))

operator = input("请输入运算符(+ 或 -): ")

num2 = float(input("请输入第二个数字: "))

if operator == "+":

result = num1 + num2

elif operator == "-":

result = num1 - num2

else:

print("无效的运算符")

exit()

print("结果是:", result)

```

JavaScript

```javascript

let num1 = parseFloat(prompt("请输入第一个数字:"));

let operator = prompt("请输入运算符(+ 或 -):");

let num2 = parseFloat(prompt("请输入第二个数字:"));

let result;

switch (operator) {

case "+":

result = num1 + num2;

break;

case "-":

result = num1 - num2;

break;

default:

alert("无效的运算符");

exit();

}

alert("结果是: " + result);

```

这些示例展示了如何在不同编程语言中实现基本的加减运算。根据你的具体需求和使用的编程语言,可以选择合适的代码片段进行参考和修改。